A) 2 sin(A) sin(B) sin(C);
B) 2 sin(A/2) sin(B/2) sin(C/2);
C) 4 sin(A/2) sin(B/2) sin(C/2);
D) 4 sin(A) sin(B) sin(C);
Kindly explain your answer...
If A,B,C are the angles of a triangle, then the value of 1 - (sin^2 (A/2) + sin^2 (B/2) + sin^2 (C/2)) is ..?
1 - (sin^2 (A/2) + sin^2 (B/2) + sin^2 (C/2))
= 1 - 1/2(2sin^2 (A/2) + 2sin^2 (B/2) + 2sin^2 (C/2))
= 1 - 1/2(1- cos A + 1- cos B + 1- cos C)
= 1/2(cos A + cos B + cos C - 1)
= 1/2(2 cos(A+B)/2 cos(A-B)/2 - 2 sin^2 (C/2))
= cos(A+B)/2 cos(A-B)/2 - cos^2 ((A+B)/2)
= cos(A+B)/2 [cos(A-B)/2 - cos(A+B)/2]
= cos(A+B)/2 * 2 * sin A/2 * sin B/2
= 2 sin A/2 sin B/2 sin C/2;
Ans B.
Reply:Try some possibilities:
1) Let A=30, B=60, C=90. Then by the half angle formula, we get that
sin^2(30/2) = [1 - cos(30)]/2 = 1/2 - sqrt(3)/4
Also sin^2(60/2) = 1/4 and sin^2(90/2) = 1/2.
So the given expression equals sqrt(3)/4 - 1/4
Expression A) is 2 * 1/2 * sqrt(2)/2 = sqrt(2)/2
Epsression B) is 2 * sqrt(3)/2 * sqrt(2)/2 = sqrt(6)/2
Expression C) is sqrt(6), twice B).
Expression D) is sqrt(2), twice A).
None of these equals the value of the expression.
nobile
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