(b-a)(c-a)(c-b)=1 1 1
a b c
a^2 b^2 c^2
prove this matrix
(b-a)(c-a)(c-b)=what matrix?
Ideas: Subtract the values of the first column from the second column and the third column, respectively.
So, the determinant
= (b-a)(c^2 - a^2) - (c-a)(b^2 - a^2)
= (b-a)(c-a)(c+a - b-a)
= (b-a)(c-a)(c-b)
Reply:I do not understand the question.
b-a=1
b=a
c-a=1
c=a
c-b=1
c=b
a=b=c=1
a b c = 1 1 1
a^2 b^2 c^2 = 1 1 1
So the Matrix is
1 1 1
1 1 1
1 1 1
Is this what you wanted to prove? The matrix should have 3 rows and 3 columns.
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